Home / Engineering & CS /6.9 and 6.10 Determine the force in each member of the truss shown. 3 m State whether each member is in tension (T) or compression (C). A C. 1.6 m 12.5kN 12.5 kN 12.5 kN 12.5 kN 8 kN 1.6 m 2.5 m Fig. P6.9

Question 6.9 and 6.10 Determine the force in each member of the truss shown. 3 m State whether each member is in tension (T) or compression (C). A C. 1.6 m 12.5kN 12.5 kN 12.5 kN 12.5 kN 8 kN 1.6 m 2.5 m Fig. P6.9

O0WEE6 The Asker · Civil Engineering

6.9

Transcribed Image Text: 6.9 and 6.10 Determine the force in each member of the truss shown. 3 m State whether each member is in tension (T) or compression (C). A C. 1.6 m 12.5kN 12.5 kN 12.5 kN 12.5 kN 8 kN 1.6 m 2.5 m Fig. P6.9
More
Transcribed Image Text: 6.9 and 6.10 Determine the force in each member of the truss shown. 3 m State whether each member is in tension (T) or compression (C). A C. 1.6 m 12.5kN 12.5 kN 12.5 kN 12.5 kN 8 kN 1.6 m 2.5 m Fig. P6.9
Community Answer
0RHI6U

&#12304;General guidance&#12305;The answer provided below has been developed in a clear step by step manner.Step1/3Solution for Truss in Fig.6.9 ( as mentioned in Question ) Support Reaction Calculation<path transform="" transform-origin="213 157" d=" M 213 157 L 213 229 " fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="3g4CpjbkiANsjTvpdaWGO"><path transform="" transform-origin="212 229" d=" M 212 229 L 321 229 " fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="zDdWmFTYveEWEjHN6UNEk"><path transform="" transform-origin="314.00000381469727 166.00000762939453" d=" M 314.00000381469727 166.00000762939453 L 345.00000381469727 166.00000762939453 " fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="1" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="xKnU"><path transform="" transform-origin="321.45 282" d=" M 333.45 282 A 11.999999999999996 11.999999999999996 0 1,0 345.45 294 A 11.999999999999996 11.999999999999996 0 0,0 333.45 282 " fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="1" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="70A6"><path transform="" transform-origin="312.45 306" d=" M 312.45 306 L 353.54999999999995 306 " fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="1" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="70A6"><path d=" M 338 157 L 373 157 " marker-end="url(#9j-SJA4xucjpBus58Tmxm-end-arrowhead)" fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="9j-SJA4xucjpBus58Tmxm"><path d=" M 338 149 L 338 122 " marker-end="url(#9j-Au5nD_NSrzs2-MmgC8-end-arrowhead)" fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="9j-Au5nD_NSrzs2-MmgC8"><path d=" M 384 298 L 357 298 " marker-end="url(#9j-Au5nD_NSrzs2-a-om--end-arrowhead)" fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="9j-Au5nD_NSrzs2-a-om-"><path d=" M 96 157 L 96 187 " marker-end="url(#9j-Au5nD_NSrzs2-a-om-l24z-end-arrowhead)" fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="9j-Au5nD_NSrzs2-a-om-l24z">8 KNRCyRCxRFx at Support C \( \begin{align*} \mathrm{R_(Cx)} & = \mathrm{\frac{{{8}\times{\left({3}+{3}\right)}}}{{{1.6}+{1.6}}}} \\& = \mathrm{{15}} \end{align*} \)\( \mathrm{{R}_{{{C}{x}}}={15}\ \text{ KN}} \) Acing away from Support \( \mathrm{{R}_{{{C}{y}}}={8}\ \text{ KN}} \) Acting Upward Now Ar Support F\( \begin{align*} \mathrm{R_(Fx)} & = \mathrm{\frac{{{8}\times{\left({3}+{3}\right)}}}{{{1.6}+{1.6}}}} \\& = \mathrm{{15}} \end{align*} \)\( \mathrm{{R}_{{{F}{x}}}={15}\ \text{ KN}} \)Acting Toward Support Explanation:Truss is Determinate and at pin 2 reactions exist and at roller only one reaction and Momnt at Both support is Zero Step2/3Now Solving Truss for Member force determination Applying at Joint C8 KN15 KNFBCFCE\( \begin{align*} \mathrm{\sum{F}_{{x}}} &= \mathrm{{0}} \\[3pt]\mathrm{{F}_{{{B}{C}}}} &= \mathrm{+{15}\ \text{ KN}} \\[3pt]\mathrm{\sum{F}_{{y}}} &= \mathrm{{0}} \\[3pt]\mathrm{{F}_{{{C}{E}}}} &= \mathrm{+{8}\ \text{ KN}} \end{align*} \)Now Applying at Joint F <path d=" M 480 270 L 394.0710678118655 184.07106781186548 " marker-end="url(#d1iCkN7LoThQH_yK-CsoD-end-arrowhead)" fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="d1iCkN7LoThQH_yK-CsoD"><path d=" M 477 270 L 477 157 " marker-end="url(#gi7p05iFd3ceRBrsT85vb-end-arrowhead)" fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="gi7p05iFd3ceRBrsT85vb"><path d=" M 522 270 L 489 270 " marker-end="url(#lgcEMLsggI_Yofh7XyrU2-end-arrowhead)" fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-edge" vector-effect="non-scaling-stroke" data-id="lgcEMLsggI_Yofh7XyrU2">15 KNFDFFEF<path transform="" transform-origin="358 270" d=" M 480 270 L 358 270 " fill="#FFFFFF" stroke="rgb(51, 51, 51)" stroke-width="2" stroke-dasharray="0" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" dominant-baseline="text-before-ed ... See the full answer

Related Questions

Problem 4.6 The bar has a cross-sectional area of 1850 mm2 and E 250 GPa 500rP N/m 1.5 m Part A Determine the displacement of its end A when it is subjected to the distributed loading Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of contraction and positive value in the case of elongation Value Units Submit My Answers Give Up
Please help solving problem 1,2 and 3. Thank you very much. For questions 1 - 3, consider the following test results obtained for a surface water sample. lon Concentration (ppm) Ca2+ 36.0 Mg2+ 10.8 Na 12.4 K 5.9 нсоз" 82.1 SO42 32.0 CI 16.9 NO3 7.4 1. Check the accuracy of the analytical measurements. Do you suspect that a constituent of significance has been neglected? If so, is it a cation or an anion? 2. Determine the mole fraction of calcium, magnesium, and sulfate for the water sample given above. 3. Determine this water's hardness and alkalinity in mg/L as CaCO3.
Die-rolling experiment: 1) Acquire any "fair-enough" die. 2) Roll it at least 100 times (each person for themselves). 3) Note what the outcome is overy time. 4) For each group of 5 (go consecutively, i.e. group first five rolls, then the next five rolls, etc.), take the average of the 5 rolls. For example, if the first five rolls are \( 3,6,1 \), 5 , and 3 , Die-rolling experiment: 1) Acquire any "fair-enough" die. 2) Roll it at least 100 times (each person for themselves). 3) Note what the outcome is overy time. 4) For each group of 5 (go consecutively, i.e. group first five rolls, then the next five rolls, etc.), take the average of the 5 rolls. For example, if the first five rolls are \( 3,6,1 \), 5 , and 3 , the average will be \( 18 / 5=3.6 \). 5) You will end up with at least 20 averages. Plot these averages on a \( 2 \mathrm{D} \) column graph. Alternatively, you can do a histogram of your results, which will be a fancier way of doing a 2D column graph. With a histogram though, you can control the bin size and instead of each individual average (e.g. 3.2, 3.4. 3.6, etc.). you can group them together with a bin size of 1 . Bonus credits will be assigned to those showing their results with a histogram of bin size 1 in addition to their regular \( 2 \mathrm{D} \) column graphs. 6) All the probabilities of \( 1,2,3,4,5 \) and 6 are \( 1 / 6 \) with a fair die. Therefore, the probabilities are said to be "uniformly distributed". Then, why is your \( 2 D \) column graph / histogram not looking uniform at all? Speculate / comment on the rationale for this.
Units V.C represents which quantity? Select one: a. Electric potential energy, U b. Electric Constant, k c. Electric Potential d. Electric Flux, F e. Electric Field, E
2-4 Estimate the TDS for one of the water samples in Problem \( 2-1 \) or \( 2-2 \) (to be selected by instructor) using Eq. (2-11) and by summing the mass of the individual ionic species. How do the computed values compare?The following test results were obtained for three treated wastewater effluent samples. Check the accuracy of the analytical 2-4 Estimate the TDS for one of the water samples in Problem \( 2-1 \) or \( 2-2 \) (to be selected by instructor) using Eq. (2-11) and by summing the mass of the individual ionic species. How do the computed values compare?The following test results were obtained for three treated wastewater effluent samples. Check the accuracy of the analytical measurements for one of the waters (to be selected by instructor). Do you suspect that a constituent of significance has been neglected? If so, is it a cation or anion? Determine the mole fraction of \( \mathrm{Ca}^{2+}, \mathrm{Mg}^{2+} \), and \( \mathrm{SO}_{4}^{2-} \) for one of the following treated wastewater effluents (to be selected by instructor).
Which of the following statements is correct regarding Kepler's three laws of planetary motion? Angular momentum of any planet about an axis through the Sun and perpendicular to the orbital plane is not invariant during its motion. Planets move in elliptical orbits with the sun not being at its center. Orbital period of a planet is directly proportional to Which of the following statements is correct regarding Kepler's three laws of planetary motion? Angular momentum of any planet about an axis through the Sun and perpendicular to the orbital plane is not invariant during its motion. Planets move in elliptical orbits with the sun not being at its center. Orbital period of a planet is directly proportional to its distance from the sun. Kepler's laws are valid only for planets in the solar system.
About
About
Blog
Sitemap
More
Help Center
Become an Expert
Download App
Legal
Terms of Service
Privacy Policy
Honor Code
Copyright Policy
Contact
contact@studyx.im
Facebook
Instagram
Twitter
YouTube
Copyright © 2023 StudyX Inc