# Question Solved1 Answer7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. the coefficient of kinetic friction is 23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts) 0000!

Transcribed Image Text: 7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. the coefficient of kinetic friction is 23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts) 0000!
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Transcribed Image Text: 7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. the coefficient of kinetic friction is 23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts) 0000!
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PLEASE UPVOTE IF YOU LIKE...... FOR ANY DOUBT PLEASE FEEL FREE TO COMMENT BELOW......HELP WILL COME QUICKLYSolution:-So,We know that, sum vec(F)=m vec(a), soF_(2)cos 21^(@)+f_(1)cos 30^(@)-f_(k)=ma.(A) Also.{:[N+F_(2)sin 21^(@)-mg-f_(1)sin 30^(@)=0],[=>quadN=F_(1)sin 30^(@)+mg-f_(2)sin 21^(@)],[=>quadN=13 sin 30^(@)+2xx9.8-11 sin 21^(@)=22 N" Ans "]:}(B) We alio know that, f_(k)=M_(k)N, so.{:[f_(k)=mu_(k)(f ... See the full answer