Question Solved1 Answer 7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. the coefficient of kinetic friction is 23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts) 0000!

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Transcribed Image Text: 7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. the coefficient of kinetic friction is 23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts) 0000!
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Transcribed Image Text: 7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. the coefficient of kinetic friction is 23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts) 0000!
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PLEASE UPVOTE IF YOU LIKE...... FOR ANY DOUBT PLEASE FEEL FREE TO COMMENT BELOW......HELP WILL COME QUICKLYSolution:-So,We know that, sum vec(F)=m vec(a), soF_(2)cos 21^(@)+f_(1)cos 30^(@)-f_(k)=ma.(A) Also.{:[N+F_(2)sin 21^(@)-mg-f_(1)sin 30^(@)=0],[=>quadN=F_(1)sin 30^(@)+mg-f_(2)sin 21^(@)],[=>quadN=13 sin 30^(@)+2xx9.8-11 sin 21^(@)=22 N" Ans "]:}(B) We alio know that, f_(k)=M_(k)N, so.{:[f_(k)=mu_(k)(f ... See the full answer