Question 7. A reaction has following mechanism: A+B=1, +1, (fast) 1, + B > P+1, (slow) 212 k> P2 where A and B are reactants, P, and P, are products, I, and I, are reaction intermediates. Find rate of reaction in terms of reactants and total order of reaction.
22G3CT The Asker · Chemistry
Transcribed Image Text: 7. A reaction has following mechanism: A+B=1, +1, (fast) 1, + B > P+1, (slow) 212 k> P2 where A and B are reactants, P, and P, are products, I, and I, are reaction intermediates. Find rate of reaction in terms of reactants and total order of reaction.
More Transcribed Image Text: 7. A reaction has following mechanism: A+B=1, +1, (fast) 1, + B > P+1, (slow) 212 k> P2 where A and B are reactants, P, and P, are products, I, and I, are reaction intermediates. Find rate of reaction in terms of reactants and total order of reaction.
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IKJQD7
Solution:-{:[A+Blongrightarrow^(K_(2))^(K_(1))I_(1)+I_(2)" (fast) "],[I_(1)+Blongrightarrow^(k_(3))P_(1)+I_(2)" (slow) "],[2I_(2)longrightarrow^(k_(4))P_(2)]:}Rate of reaction must be calculated from{:[" Slow ste "P],[:.quad" Rate "=K_(3)[I_(1)]^(')[B]^(')longrightarrow(1)]:}since I_(1) is intermediate it must not involve in rate Law.From equilibrium equation" equilibrium constant "=(k_(1))/(k_(2))(K_(1))/(K_ ... See the full answer