Queuing Simulation
Material B: 100kgs Interarrival time: 5 mins
Material B: 100kgs Interarrival time: P(2) = 0.25 P(3) = 0.75
Answer:-Poge-1As per given detoilsMatcrial weight(kg) Interarrivel Time (minuter){:[" A ",200,5+-2" (unif)xm) "],[B,100,G(con 5tan t)],[C,50,P(2)=0.33 P(3)=0.67]:}Material A(20okg ∣ box){:[3,0.2,0.2,1.2],[4,0.2,0.4,3-4],[5,0.2,0.6,5-6],[6,0.2,0.8,7-8],[7,0.2,1.0,9-0]:}Poge-2{:[" Box "," RD for "," Interirdivol "," clock time "],[," interval time "," time ",3],[1,1,3,7],[2,4,4,13],[3,5,6,vdots],[14,vdots,vdots],[" Moteriol "," B "(100kg" lbox "),],[,,],[" Box "," clock time ",],[1,6 ... See the full answer