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\begin{array}{l}P=1000 \mathrm{lbf} / \mathrm{ft} t^{2} \\V=6.5 \mathrm{ft}^{3} / \mathrm{lbm} \\h=9800 \mathrm{lbf}-\mathrm{ft} / 1 \mathrm{bm} .\end{array}From formula\begin{aligned}h & =u+p v \\\Rightarrow \quad u & =h-p v\end{aligned}p \rightarrow pressurev \rightarrow specific volume\begin{aligned}u & =9800-\left(1000 \frac{\mathrm{lbf}}{f t^{2}}\right) \times\left(\frac{6.5 f t^{3}}{l b m}\right) \\& \Rightarrow(9800-6500) \frac{1 b f-f t}{l b m} \\u & \Rightarrow 3300 \frac{\mathrm{lbf}-f t}{l b m}\end{aligned}(b) Auswer ...