Question Solved1 Answer 6. (Submit a screenshot of your written or typed answer) Suppose a student has a midterm mark of 60 , calculate the z-score for this student. Keep 3 decimals. Provide an explanation that you would say to someone about this \( z- \) score who does not have statistics knowledge. 7. (Submit a screenshot of your written or typed answers for parts a to e) Based 6. (Submit a screenshot of your written or typed answer) Suppose a student has a midterm mark of 60 , calculate the z-score for this student. Keep 3 decimals. Provide an explanation that you would say to someone about this \( z- \) score who does not have statistics knowledge. 7. (Submit a screenshot of your written or typed answers for parts a to e) Based on the given data, a. Identify the sample and the population b. The mean you calculated in question 4 is a parameter. True or False? c. How would you name the data based on the measurement scale (nominal, ordinal, interval, and ratio) d. The data is obtained by using probability sampling or non-probability sampling? e. If you want to conduct a study about this data, is the study observational study or design of experiment?

6VZOUZ The Asker · Probability and Statistics

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Transcribed Image Text: 6. (Submit a screenshot of your written or typed answer) Suppose a student has a midterm mark of 60 , calculate the z-score for this student. Keep 3 decimals. Provide an explanation that you would say to someone about this \( z- \) score who does not have statistics knowledge. 7. (Submit a screenshot of your written or typed answers for parts a to e) Based on the given data, a. Identify the sample and the population b. The mean you calculated in question 4 is a parameter. True or False? c. How would you name the data based on the measurement scale (nominal, ordinal, interval, and ratio) d. The data is obtained by using probability sampling or non-probability sampling? e. If you want to conduct a study about this data, is the study observational study or design of experiment?

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Ques.6 Let score be X mean score, mu=69.93 standard deviation of scores= sigma=19.002 z-score: z=(x-mu)/(sigma)z=(x-mu)/(sigma)z=(x-mu)/(sigma) z=(x-69.3)/(19.002) Now, here x=60(given) z=(60-69.3)/(19.002) z=-0.489 Negative z ... See the full answer

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