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Solution:- Since the thickness of the standard piece of paper =0.05mm.a) Now if we fold the paper, the thickness of the folded paper will be double.Hence, thickners =(0.05)xx2.If we again fold the paper, the thickness will be again 2 times the previous one." Hence, thicknss "{:[=(0.05)xx2xx2],[=(0.05)xx2^(2).]:}Hence, let the paper is folded n times, then the function g(n) will be given byg(n)=0.05 xx2^(n)mmb) Now, let the thicknes of the paper after foldingn" times "=tthen, g(n)=t{:[=>quad t=(0.05)xx2^(n).],[=>quad2^(n)=(t)/( 0.05) ... See the full answer