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6 k r / m1.5 \uparrow \leftarrow_{A x} 31.5R_{A}R_{B}The beam is symmetric\Rightarrow Reactions coill be equal\begin{array}{l} \sum F_{y}=0 \\R_{A}+R_{B}=6 \times 1.5+9 \times 3+6 \times 1.5 \\=45 \\\therefore R_{A}=R_{B}=\frac{45}{2}=22.5 \mathrm{kN}\end{array}\Sigma F_{x}=0R_{A x}=0please do appreciate it by giving it a thumbs up. Thanks ...