If Y has a binomial distribution with n trials and probability of success p, the moment-generating function for Y is m(t) = (pet + q)n, where q = 1 − p. If Y has moment-generating function m(t) = (0.8et + 0.2)10, what is P(Y ≤ 9)? (Round your answer to three decimal places.) P(Y ≤ 9) =

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Solution:if y follow binomial distai bution 4∼B(n,p)then Maf of y, punf p(y=y)=([n],[y])p^(y)(1-p)^(n-y) {:M_(y)∣t)=(1-p+pet)^(n)◻Deltaatven maf theta+y{:[{:[" My "1+1=(0.8e^(t)+0.2)^(10)],[" com pare "eq" (1) "s" (11). "],[p=0.8","8quad n=10. ... See the full answer