QUESTION

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A $0.2500 \mathrm{~g}$ sample of swimming pool oxidizer containing calcium hypochlorite as the active ingredient was dissolved in $0.50 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ containing $\mathrm{KI}$. The liberated iodine required $38.2 \mathrm{~mL}$ of $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$. The titrant was standardized by titrating 101.3 $\mathrm{mg} \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ dissolved in acid with the action of excess $\mathrm{KI}$, which required $17.4 \mathrm{~mL}$ of the $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$. Calculate the $\% \mathrm{Ca}(\mathrm{OCl})_{2}$ in the sample.

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