Question Solved1 Answer (a) (3 pts) For each of the following signals, determine both energy and power, and classify whether the signal is an energy signal, power signal, or neither of the two. Justify your answers. i. (1 pt) x(t) = e-2tu(t). ii. (1 pt) x(t) = cos(t) iii. (1 pt) x(t) = ej(2t+A/4) (b) (2 pts) Let g(t) = e-ct, where c is a complex number with a strictly positive real part, say c= = a+jb with a > 0. Determine if g(t) is an energy or a power signal (or neither).

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Transcribed Image Text: (a) (3 pts) For each of the following signals, determine both energy and power, and classify whether the signal is an energy signal, power signal, or neither of the two. Justify your answers. i. (1 pt) x(t) = e-2tu(t). ii. (1 pt) x(t) = cos(t) iii. (1 pt) x(t) = ej(2t+A/4) (b) (2 pts) Let g(t) = e-ct, where c is a complex number with a strictly positive real part, say c= = a+jb with a > 0. Determine if g(t) is an energy or a power signal (or neither).
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Transcribed Image Text: (a) (3 pts) For each of the following signals, determine both energy and power, and classify whether the signal is an energy signal, power signal, or neither of the two. Justify your answers. i. (1 pt) x(t) = e-2tu(t). ii. (1 pt) x(t) = cos(t) iii. (1 pt) x(t) = ej(2t+A/4) (b) (2 pts) Let g(t) = e-ct, where c is a complex number with a strictly positive real part, say c= = a+jb with a > 0. Determine if g(t) is an energy or a power signal (or neither).
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Please go through the pictures...... Solution(1)(a) E( Energy )=int_(-oo)^(oo)|x(t)|^(2)dt : for bo th periodicP={[1//T_(0)int_(T0)^(-oo)|x|t||^(2)dt;],[lim_(T rarr oo)(1)/(T)int_(-T//2)^(T//2)|x(d)|^(2)dt;" Periodic Signals "],["; Signals "]:}(i) x∣t1=e^(-2t)u(t)quad u(t)={[0;,t < 0],[1;,t⩾0]:}So, E=int_(-oo)^(oo)|x(t)|^(2)dt quad So, e^(-2t)u(t)={[0;,t < 0],[e^(-2t);,t⩾0]:} E=int_(-oo)^(0)0dt+int_(0)^(oo)|e^(-2t)|^(2)dt=>E=0+int_(0)^(oo)e^(-4t)dt E=[(e^(-4t))/(-4)]_(0)^(oo)=>E=(e^(-oo)-e^(0))/(-4)=>E=(0-1)/(-4)E=1//4=> Finite so it is an exergy signal. (if E= finite the Av ... See the full answer