A 3.00-kg block is sent up a ramp inclined at an angle 𝜃=29.0∘ from the horizontal. It is given an initial velocity 𝑣0=15.0 m/s up the ramp. Between the block and the ramp, the coefficient of kinetic friction is 𝜇k=0.50 and the coefficient of static friction is 𝜇s=0.80. What distance 𝐷 in m along the ramp's surface does the block travel before it comes to a stop?
The block will travel 17.6 m along the ramp's surface before it comes to stop To start moving the object (block), we have to give the force to the block to overcome the static frictions. This force required to set in motion must be greater than the difference besween the component of weight along the ramp and the static orictional jorce.The normal force is N=mg cos thetaNow f Should brF >= (mu_(k)+mu_(s))N-mg sin thetaWhere, mu_(K)= co-efficient of kinefic frietion =0.50 (given)mu_(s)=c0-efficient of static friction=0.80 (given)m= man of the blockg= gravitational accelaration =9.81m//s^ ... See the full answer