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Step 1Given that,Diameter = 36.0 cmMagnetic field = 1.8 TTime = 0.40 sStep 2We will use the formula of average induced emf in the loopThe formula of average induced emf in the loop is \begin{array}{l}\varepsilon_{\text {avg }}=-N \frac{d \phi}{d t} \\ \varepsilon_{\text {arg }}=-N \frac{d(B A)}{d t}\end{array}Where N = number of turnsB = magnetic fieldA = Areat = time Step 3We need to calculate the average induced emf in the loopUsing the formula of the average induced emf in the loop\begin{array}{l}\varepsilon_{\text {avg }}=N \frac{d \phi}{d t} \\ \varepsilon_{\text {avg }}=N \frac{d(B A)}{d t}\end{array}Put the value into the formula\begin{array}{l}\varepsilon_{\text {avg }}=\frac{1 \times 1.8 \times \pi \times\left(18 \times 10^{-2}\right)^{2}}{0.40} \\ \varepsilon_{\text {arg }}=0.0045 \mathrm{~V} \\ \varepsilon_{\text {arg }}=4.5 \mathrm{mV}\end{array} Step 4The average induced emf in the loop is 4.5 mV. ...