A 600mm diameter pipeline carries water under a head of 30m with a velocity of 3m/s this water main is fitted with a horizontal bend which turns the axis of the pipeline through 75°[i.e the internal angle at the bend is 105°]. calculate the resultant force on the bend and it's angle to the horizontal

See Answer

Add Answer +20 Points

Community Answer

See all the answers with 1 Unlock

Get 4 Free Unlocks by registration

Get 4 Free Unlocks by registration

Q) Given:-Soln:-{:[D=60cmm],[h=30m],[v=3m//s]:}(a) Resuctant Ferce :-We hare," And "{:[P_(1)=egh=10^(3)xx9.81 xx30=294.3kN//m^(2)],[Q*VA=3((pi)/(4)(600 xx10^(3)))=0.84m^(3)//s],[F_(x)=equ^(2)(cos 75^(@)-cos 0)],[F_(x)=10^(3)(0.34)(3)(cos 75^(@)-1)],[longrightarrowF_(x)=-1856N],[F_(y)=eQu(sin 75-sin 0)=10^(3)xx","0.84 xx3(sin 75)],[rarrF_(y)=2457N//]:}Haepressure face on ' x ' direction{:[P_(x)=PA(cos 0-cos 75)],[P_(x)=0.283(294.3)(1-cos 75)],[rarrP_ ... See the full answer