A 72 kg skydiver can be modeled as a rectangular "box" with dimensions 18 cm × 44 cm × 180 cm . If he falls feet first, his drag coefficient is 0.80.

What is his terminal speed if he falls feet first? Use ρ = 1.2 kg/m3 for the density of air at room temperature.

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The area of cross section of rectangulas bor is,\begin{array}{c}A=l b=1.8 \times 44=792 \mathrm{~cm}^{2} \\=0.0792 \mathrm{~m}^{2} \\V_{t}=\sqrt{\frac{2 \mathrm{mg}}{\text { PACd }}}=\sqrt{\frac{2(72)(9.8)}{1.2(0.0792)(0.8)}} \\=1.36 .23 \mathrm{~m} / \mathrm{s}\end{array} ...