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Please check the answers and comment below if you don't understand any steps and calculation. Thank you for the question.Part A:- Friction force ow the block is F_{\mu}=\mu R=\mu \omega \cos \thetaTotal disfance =LWork dine by friction firceR=m g \cos \theta=\omega \cos \theta\begin{array}{l}W_{f}=\vec{F}_{\mu} \cdot \vec{L}=-\mu \omega L \cos \theta \\W_{f}=-\mu \omega L \cos \theta\end{array}\sin g_{2}comes ans \vec{F}_{\mu} and \vec{L} are opposite to each otherA MPartB:- Equation of motion by the force F(F-\operatorname{Mg} \sin \theta)=M a \quad a=0 as comfut velocity is there F=\omega \sin \thetaWoxk done by the force \omega=\vec{F} \cdot \vec{L}=L \omega \sin \thetaW=L W \sin \theta \text { Am }Part e:- Total work done = change in energs of the blockAs no finetic energs is there in the blockSo Total work done = change iw potenfial energs\begin{array}{c}\Rightarrow \Delta u=\Sigma w=W+w_{f} \\\Delta u=L W \sin \theta-\mu L \omega \cos \theta \\\Delta u=L \omega \sin \theta-\mu \cos \theta \mathrm{Am}\end{array} ...