a cable BA shown in the figure is fixed so that the resultant force exerted on the pole is directed along its axis, from B toward O.

determine x & y coordinates of the end A of the cable BA.

determine the magnitude of the resultant force.

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Given that F_(1)=350N,F_(2)=250N,F_(3)=300N{:[A(x","y","0)quad B(0","0","4)","C(-3","0","0)],[Delta(2","-3","0)],[ vec(F_(1))=| vec(F_(1))|xx( vec(BC))/(| vec(BC)|)],[=350 xx(-3( hat(i))-4( hat(k)))/(sqrt((-3)^(2)+(-4)^(2)))],[ vec(F_(1))=70(-3 hat(i)-4 hat(k))]:}{:[ vec(F)_(2)=F_(2)xx( vec(BD))/(| vec(BD)|)=250 xx(2( hat(i))-3( hat(j))-4( hat(k)))/(sqrt(4+9+16))],[ vec(F_(2))=(250)/(sqrt29)(2 hat(i)-3 hat(j)-4 hat(k))],[ vec(F_(3))=F_(3)xx( vec(BA))/(| vec(BA)|)=300((x( hat(i))+y( hat(j))-4( hat(k)))/(sqrt(x^(2)+y^(2)+16)):}]:}:' regultantant force along BO vec(F)_(R)= vec(F)_(1)+ vec(F)_(2)+ vec(F)_(3){:[ vec(F)_(R)=-210 hat(i)-280 hat(k)+(250)/(sqrt29)(2 hat(i)-3 hat(j)-4 hat(k))],[+300((x( hat(i))+y( hat(j))-4( hat(k)))/(sqrt(x^(2)+y^(2)+16)))]:}Resultant force along x-axis =0-210+(500)/(sqrt29)+(300 x)/(sqrt(x^(2 ... See the full answer