As of my knowledge I have answered this question 100%.Hope you like it still if you have any doubts means please comment but don't dislike,Thank you... SOLUTION:As per thegiven data Solutione As per the given data.vol. flow rate (v^(@))=0.800L//hHeating value =3.25 xx10^(4)k8//cSo power (p)=(0.800)L//hxx3.4 xx10^(4)(KJ)/(L)xx(1hg_(8))/(3600sec). R_("original ")=7.22kJ//s=7.22kW.So. now actual power 6 quad Efticiency = Actual power / Roriginal. Pactual =(7.22)(0.34)=2. ... See the full answer