Question Solved1 Answer A certain gasoline engine has an efficiency of 34.0%; that is, it converts into useful work 34.0% of the heat generated by burning a fuel. Power Correct. If the engine consumes 0.800 L/h of a gasoline with a heating value of 3.25 x 104 kJ/L, how much power does it provide? Calculate the answer in kilowatts and horsepower. 2.45 kW 3.28 hP e Textbook and Media Hint Attempts: 3 of 3 used Mixture Consumption Suppose the fuel is changed to include 25.0% ethanol by volume. The heating value of ethanol is approximately 2.34 x 104 kJ/L and volumes of gasoline and ethanol are assumed to be additive. At what rate (L/h) does the fuel mixture have to be consumed to produce the same power as gasoline (consumed at 0.800 L/h)? L/h

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Transcribed Image Text: A certain gasoline engine has an efficiency of 34.0%; that is, it converts into useful work 34.0% of the heat generated by burning a fuel. Power Correct. If the engine consumes 0.800 L/h of a gasoline with a heating value of 3.25 x 104 kJ/L, how much power does it provide? Calculate the answer in kilowatts and horsepower. 2.45 kW 3.28 hP e Textbook and Media Hint Attempts: 3 of 3 used Mixture Consumption Suppose the fuel is changed to include 25.0% ethanol by volume. The heating value of ethanol is approximately 2.34 x 104 kJ/L and volumes of gasoline and ethanol are assumed to be additive. At what rate (L/h) does the fuel mixture have to be consumed to produce the same power as gasoline (consumed at 0.800 L/h)? L/h
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Transcribed Image Text: A certain gasoline engine has an efficiency of 34.0%; that is, it converts into useful work 34.0% of the heat generated by burning a fuel. Power Correct. If the engine consumes 0.800 L/h of a gasoline with a heating value of 3.25 x 104 kJ/L, how much power does it provide? Calculate the answer in kilowatts and horsepower. 2.45 kW 3.28 hP e Textbook and Media Hint Attempts: 3 of 3 used Mixture Consumption Suppose the fuel is changed to include 25.0% ethanol by volume. The heating value of ethanol is approximately 2.34 x 104 kJ/L and volumes of gasoline and ethanol are assumed to be additive. At what rate (L/h) does the fuel mixture have to be consumed to produce the same power as gasoline (consumed at 0.800 L/h)? L/h
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As of my knowledge I have answered this question 100%.Hope you like it still if you have any doubts means please comment but don't dislike,Thank you... SOLUTION:As per thegiven data Solutione As per the given data.vol. flow rate (v^(@))=0.800L//hHeating value =3.25 xx10^(4)k8//cSo power (p)=(0.800)L//hxx3.4 xx10^(4)(KJ)/(L)xx(1hg_(8))/(3600sec). R_("original ")=7.22kJ//s=7.22kW.So. now actual power 6 quad Efticiency = Actual power / Roriginal. Pactual =(7.22)(0.34)=2. ... See the full answer