A circular coil enclosing an area of 100 cm2 is made of 200 turns of copper wire. The wire making up the coil has resistance of 5.0 V, and the ends of the wire are connected to form a closed circuit. Initially, a 1.1-T uniform magnetic field points perpendicularly upward through the plane of the coil. The direction of the field then reverses so that the final magnetic field has a magnitude of 1.1 T and points downward through the coil. If the time required for the field to reverse directions is 0.10 s, what is the average current in the coil during that time?
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Step 1It is given that,\begin{aligned} A & =100 \mathrm{~cm}^{2} \\ n & =200 \\ R & =5 \Omega \\ B_{i} & =1.1 \mathrm{~T} \\ B_{f} & =1.1 \mathrm{~T} \\ t & =0.10 \mathrm{~s}\end{aligned}Step 2The induced emf is given as,\begin{aligned} \varepsilon & =n\left(\frac{\Delta \phi}{t}\right) \\ & =-200\left(\frac{\Delta B A}{0.1}\right) \\ I R & =-200 \times\left(\frac{(-1.1-1.1) 100 \times 10^{-4}}{0.1}\right) \\ I \times 5 & =200 \times \frac{0.022}{0.1} \\ I & =88 \mathrm{~A}\end{aligned}AnswerThe average current flowing through the coil is = 88 A ...