Question Solved1 Answer A circular shaft is actued upon by a combination of loadings: an applied torque that produces a constant shear stress of 56 MPa, an axial force that produces a constant normal stress of 70 MPa, and a bending moment that produces a completely reversed normal stress of +140 MPa. Determine the factor-of-safety (n) using the Goodman theory for combined loading. The shaft is machined to a diameter of (2.5 cm) and has a keyway that results in a reduced stress concentration factor (Kf) equal to (1.15). The shaft operates at 100 °C. Also, the ultimate tensile strength (Sut) is 525 MPa.

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Transcribed Image Text: A circular shaft is actued upon by a combination of loadings: an applied torque that produces a constant shear stress of 56 MPa, an axial force that produces a constant normal stress of 70 MPa, and a bending moment that produces a completely reversed normal stress of +140 MPa. Determine the factor-of-safety (n) using the Goodman theory for combined loading. The shaft is machined to a diameter of (2.5 cm) and has a keyway that results in a reduced stress concentration factor (Kf) equal to (1.15). The shaft operates at 100 °C. Also, the ultimate tensile strength (Sut) is 525 MPa.
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Transcribed Image Text: A circular shaft is actued upon by a combination of loadings: an applied torque that produces a constant shear stress of 56 MPa, an axial force that produces a constant normal stress of 70 MPa, and a bending moment that produces a completely reversed normal stress of +140 MPa. Determine the factor-of-safety (n) using the Goodman theory for combined loading. The shaft is machined to a diameter of (2.5 cm) and has a keyway that results in a reduced stress concentration factor (Kf) equal to (1.15). The shaft operates at 100 °C. Also, the ultimate tensile strength (Sut) is 525 MPa.
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Shear stresS =S6HPQ=tau(6a) Axial Normal stres.s = 70 HPa Bending stress =+-146HPaVonmises stress{:[" Alternating stress "=sqrt(6_(a)^(2)+3tau^(2))=140HPa],[" Meanstress "=sqrt(6m_(2)^(2)+3tau_(m)^(2))],[quadsigma_(m)=sqrt((140)^(2)+3(56)^(2))=119.62HPa.]:}Endurance limit modytying fectorSurtate factor a(" sut ")^(b)=4.51(5.25)^(-0.265)=0.858" size tactor "=(0.858-0.000837(63.5))=0.806Cocid fuctor 1{:[S_(e)= ... See the full answer