Step 1SolutionGiven data;PV=0.08206 nTStep 2(a) Absolute pressure is equal to gauge pressure plus atmospheric pressure.Use 1 atm for P,11 for V,273.15K for T and 1 mol for n.R=(PV)/(nT)" (1). "converiting P in I psi1 atm =14.70 psiconverting V in ft^(3)1L=0.035ft^(3)corverting T in of273.15K=32^(@)FConverting 1 mol is lb-mol 1mol=1lb-molSubstitute the convented values in(1);Step 3{:[R=((14.70psi)(0.035 ft^(3)))/((1lb-mol)(32^(@)F))],[R=0.016psi-ft^(3)//lb-mol|^(@)F]:}(b) CO=30 mole %Nitrogen, N=70 mole 1. Cylinder volume, V_(1) ... See the full answer