# Question A cylindrical blood vessel is partially blocked by the buildup of plaque. At one point, the plaque decreases the diameter of the vessel by 62.0%. The blood approaching the blocked portion has speed 𝑣0. Just as the blood enters the blocked portion of the vessel, what is its speed 𝑣, expressed as a multiple of 𝑣0?𝑣=

&#12304;General guidance&#12305;The answer provided below has been developed in a clear step by step manner.Step1/2solution:we know that by continuity equation we have\begin{align*} \mathrm{{A}_{{1}}{V}_{{1}}} &= \mathrm{{A}_{{2}}{V}_{{2}}} \end{align*}hereA=areaV=velocityso at first let for a diameter of d the area of the vessel is given by\begin{align*} \mathrm{{A}_{{1}}} &= \mathrm{\pi{\left(\frac{{d}^{{2}}}{{4}}\right)}} \end{align*}now given that the diameter is decreased by 62% so the area is given by\( \begin{align*} \mathrm{{A}_{{2}}} &= \mathrm{\pi{\left(\frac{{\left({d}-\frac{{{62}{d}}} ... See the full answer