Question Solved1 Answer A dipole is centered at the origin, and is composed of particles with charges +e and -e, separated by a distance 0.3 nm along the y-axis. The +e charge is on the -y-axis and the -e charge is on the ty-axis. A proton is located at < 80,0,0 > nm. What is the force on the proton due to the dipole? 3.15*10^-34 b 0 > x 3.15 . 10-34 0 0 Determine where you should place an electron so that the net force (from the dipole and the electron) on the proton will be zero. 4 0 0 > x

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Transcribed Image Text: A dipole is centered at the origin, and is composed of particles with charges +e and -e, separated by a distance 0.3 nm along the y-axis. The +e charge is on the -y-axis and the -e charge is on the ty-axis. A proton is located at < 80,0,0 > nm. What is the force on the proton due to the dipole? 3.15*10^-34 b 0 > x 3.15 . 10-34 0 0 Determine where you should place an electron so that the net force (from the dipole and the electron) on the proton will be zero. 4 0 0 > x
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Transcribed Image Text: A dipole is centered at the origin, and is composed of particles with charges +e and -e, separated by a distance 0.3 nm along the y-axis. The +e charge is on the -y-axis and the -e charge is on the ty-axis. A proton is located at < 80,0,0 > nm. What is the force on the proton due to the dipole? 3.15*10^-34 b 0 > x 3.15 . 10-34 0 0 Determine where you should place an electron so that the net force (from the dipole and the electron) on the proton will be zero. 4 0 0 > x
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Here we can use the properties of dipole and forces due to it at a distance from it, In second part we will assume a charge at distance ra from the +ve charge and find distance and coordinates. Jor a dipole, feild at perpendicular bisector,E=(1)/(4piepsilon_(0))(qd)/((r^(2)+((d)/(2))^(2))^(3//2))here r≫d, so neglecting d//2 term, new charge{:[E=(1)/(4pi6_(0))(qd)/(gamma^(3))=8//9xx1phi^(2)alpha],[f=qE=(1)/(4piepsilon_(0))xx(q^(2)d)/(r^(3))=8.9 xx10^(9)xx((1.6 xx10^(-19))^(2)xx(0 ... See the full answer