A firefly glows by the direct conversion of chemical energy to light. The light emitted by a firefly has peak intensity at a wavelength of 550 nm. a. What is the minimum chemical energy, in eV, required to generate each photon? b. One molecule of ATP provides 0.30 eV of energy when it is metabolized in a cell. What is the minimum number of ATP molecules that must be consumed in the reactions that lead to the emission of one photon of 550 nm light?

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\text { Wavelength }=\lambda=550 \mathrm{~nm}=550 \times 10^{-9} \mathrm{~m} \text {. }(A)\begin{aligned}\text { Eneogy of photon } & =\frac{h c}{\lambda} \\& =\frac{6.626 \times 10^{-34} \times 3 \times 10^{8}}{550 \times 10^{-9}} \\& =3.6141818 \times 10^{-19} \mathrm{Jovle} \\& =2.258864 \mathrm{eV} .\end{aligned}Ans(B)\begin{array}{l}\text { Wevelength }=\lambda=550 \times 10^{-9} \mathrm{~m} \text {. } \\\text { Eneggy of photon }=2.258864 \mathrm{eV} \text {. }\end{array}Eneggy of one molecule of ATP =0.30 \mathrm{eV}.\begin{array}{l}\text { so, Number of Molecule }=\frac{2.258864}{0.30} \\=7.52954 \text { molecule } \\\end{array}so, Reecired morecule =8.Ans ...