Solution:-Velocity of the jet, v_(J)=1200km//hrAbove is an example of horizoutal projectile motion:-Intial velocity, u of the cargo is in the horizontal direction:Applying equation of motion in x direction.S_(x)=u_(x)++(1)/(2)a_(x)t^(2)S_(x)=> displacementt=> time takenSince; there is no acceleration in x-direction.So; a_(x)=0{:[S_(x)=u_(x)+],[uarr],[" Range "=>R=u*t]:}Now; to find t :-(a.) Using equation of motion in y direction:-s_(y)=u_(y)t+ ... See the full answer