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Solutiona) Ans Given that, \gamma=3.5 \%=0.035, t=10 yearsn=4 \text {, Future value }=\$ 60000so,\begin{aligned}& P\left[\left(1+((r / n)]^{n t}-1\right] /(r / n)=60000\right. \\\Rightarrow & \frac{P\left[\left(1+(0.035 / 4)^{4 \times 10}-\right]\right.}{0.035 / 4}=60000 \\\Rightarrow & P=60000 \times(0.035 / 4)\left[\left(1+(0.035 / 4)^{4 \times 10}-1\right]\right. \\\Rightarrow & P=\frac{60000 \times(0.035 / 4)}{1+(0.035 / 4)^{40}-1}=1259.27\end{aligned}\therefore John should deposit S_{1} 1259.27 quarterly.b) The Marginal Cost (MC) of producing a certuin good is set as M C=\$ 15+0.0025 QThe good selling price is, P=535.00Now, Since profil- is maximized where the selling price is equal to the Marginal Cost-.So, M C=P\begin{array}{l}\Rightarrow 15+0.0025 Q=35 \\\Rightarrow 0.0025 Q=20 \\\Rightarrow Q=8000\end{array}\therefore The pofil- maximizing quantity of output is 8000 . If you have any doubt please ask me in a comment section. And if you like my solution please give me a thumbs-up. Thank you have a great day. ...