Can you explain in very simple terms please?

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In rod,{:[" We know, "],[v_("s,rod ")=nulambda_(lod)],[(v)=2pi f],[=>nu=(V_(sin))/(lambda)],[=(eta_(s,gammasigma_(d)))/(2l)],[=(1500)/(2xx0.45)quad[v_(s_(1)m_(2))=1500(m)//s]]:}As frequency or angulm frequency doesn't charge in medium so,{:[nu_("S,at ")=nu lambda],[=>lambda=(V_("s, air "))/(nu)=(300)/(1500//2xx0.45)],[=(300 xx2xx0.45)/(1500)],[=0.18m]:}:." Wavelength in air "{:[lambda=0.18m],[=18cm]:}:. option-C ... See the full answer