Question Solved1 Answer Can you explain in very simple terms please? A metal rod of length 45 cm is clamped at its mid point. The speed of [1 mark] sound in the metal rod is 1500 m s-1 and the speed of sound in air is 300 ms-1. The metal rod vibrates at its first harmonic. What is the wavelength in air of the sound wave produced by the metal rod? A. 4.5 cm B. 9.0 cm C. 18 cm D. 90 cm

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Can you explain in very simple terms please?



Transcribed Image Text: A metal rod of length 45 cm is clamped at its mid point. The speed of [1 mark] sound in the metal rod is 1500 m s-1 and the speed of sound in air is 300 ms-1. The metal rod vibrates at its first harmonic. What is the wavelength in air of the sound wave produced by the metal rod? A. 4.5 cm B. 9.0 cm C. 18 cm D. 90 cm
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Transcribed Image Text: A metal rod of length 45 cm is clamped at its mid point. The speed of [1 mark] sound in the metal rod is 1500 m s-1 and the speed of sound in air is 300 ms-1. The metal rod vibrates at its first harmonic. What is the wavelength in air of the sound wave produced by the metal rod? A. 4.5 cm B. 9.0 cm C. 18 cm D. 90 cm
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In rod,{:[" We know, "],[v_("s,rod ")=nulambda_(lod)],[(v)=2pi f],[=>nu=(V_(sin))/(lambda)],[=(eta_(s,gammasigma_(d)))/(2l)],[=(1500)/(2xx0.45)quad[v_(s_(1)m_(2))=1500(m)//s]]:}As frequency or angulm frequency doesn't charge in medium so,{:[nu_("S,at ")=nu lambda],[=>lambda=(V_("s, air "))/(nu)=(300)/(1500//2xx0.45)],[=(300 xx2xx0.45)/(1500)],[=0.18m]:}:." Wavelength in air "{:[lambda=0.18m],[=18cm]:}:. option-C ... See the full answer