Question Solved1 Answer A pomegranate is thrown from ground level straight up into the air at time t=0 with a velocity of 192 feet per second. Its height in feet at tt seconds is f(t)=−16t^2+192t. Find the time it hits the ground and the time it reaches its highest point.Hits the ground when t= (include units)Reaches the highest point when t=  (include units)Maximum height = 

PBMDCF The Asker · Calculus

A pomegranate is thrown from ground level straight up into the air at time t=0 with a velocity of 192 feet per second. Its height in feet at tt seconds is f(t)=−16t^2+192t. Find the time it hits the ground and the time it reaches its highest point.
Hits the ground when t= (include units)
Reaches the highest point when t=  (include units)
Maximum height = 

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Step 1A pomegranate is thrown straight up into the air with velocity of 192 ft/sec at t = 0 sec.Find the maximum height reached and time to reach the maximum height and to hit the ground.Step 2Q Height of Pomegranate,f(t)=-16t^(2)+192 t" (feet) "It is thrown straight up into the air at t=0, with velocity 192ft//sec.:." velocity ",(df(t))/(dt)=-32 t+192". ... See the full answer