Question Solved1 Answer A proton with a charge of 1.60X10^(-19) C is shot from plate B toward plate A with a speed of 1.5X10^(-6) m/s. ( d = 0.0030 m) (a) What is the electric potential between the plates? (b) What will the speed of the proton be just before it hits plate A? *

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A proton with a charge of 1.60X10^(-19) C is shot from plate B toward plate A with a speed of 1.5X10^(-6) m/s. ( d = 0.0030 m) (a) What is the electric potential between the plates? (b) What will the speed of the proton be just before it hits plate A? *

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Plate(A) Plate(B)Y=1.5 xx10^(-6)m//sec,q=1.6 xx10^(-19)CPotential =(" wonk ")/(q)=(" Change in "K*E)/(q)=(Delta K)/(q)(a){:[" Potential "=(kq)/(d)=(9xx10^(9)xx1.6 xx10^(-9))/(0.003)],[=(9xx1.6)/(3)xx10^(9-19+3)],[=(1.44 xx10^(-7))/(3)=0.48 xx10^(-7)Volt]:}(b) No{:[" Naw, Potential "=(Delta K)/(q)=(( ... See the full answer