A rectangular block of wood, 10.0 cm×15.0 cm×26.0 cm, has a specific gravity of 0.600.
Determine the buoyant force Fb that acts on the block when it is placed in a pool of freshwater with a density of 1.00×10^3 kg/m3
Fb= 22.932 N
What fraction 𝑓f of the block is submerged? <<<< just need this
Determine the weight 𝑤w of the water that is displaced by the block. ww= 22.932N
Fram Equilibrium, F_(B)=W{:[:.F_(B)=W=10 xx15 xx26 xx(0.6 xx1)g],[=2340g=(2340)/(1000)xx9.81N],[=22.95N.]:}But given weight of block is 22.932N.:. Buoyant force =F_(B)=22.932NNow, F_(B)=W{:[=>r_(w)xxV_("sub ")=r_(" ... See the full answer