Community Answer

a) Force on a segment of wire of length 1, carrying current I, due to magnetic field B, is given byvec(F)=I vec(l)xx vec(B)Since direction of segment ab is along{:[+y"-axis and " vec(B)=B*(cos 40^(@)( hat(y))+sin 40^(@)( hat(z)))],[ vec(F)_(ab)=Iint_(ab) hat(y)xx B(cos 40^(@)( hat(y))+sin 40^(@)( hat(z)))],[ vec(F)_(ab)=Il_(ab)B sin 40^(@) hat(x)]:}direction of magnetic force is " +x-axis".direction, -2 axis" c) "{:[F_(Cd)=I vec(l)_(CD)xx vec(B)],[=Il_(CD)(- hat(y))xx B(cos 40^(@)( hat(y))+sin 40^(@)( ... See the full answer