Question Solved1 Answer A Review Constants A vertical, 1.10 m length of 18 gauge (diameter of 1.024 mm) copper wire has a 100.0 N ball hanging from it. Express your answer with the appropriate units. X = 0.733 m Submit Previous Answers ✓ Correct Part B A 500.0 N ball now replaces the original ball. What is the change in the wavelength of the third harmonic caused by replacing the light ball with the heavy one? Hint Young's Modulus for copper is 11 x 100 Pa Express your answer with the appropriate units. UA ? Δλ = Value m Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining

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Transcribed Image Text: A Review Constants A vertical, 1.10 m length of 18 gauge (diameter of 1.024 mm) copper wire has a 100.0 N ball hanging from it. Express your answer with the appropriate units. X = 0.733 m Submit Previous Answers ✓ Correct Part B A 500.0 N ball now replaces the original ball. What is the change in the wavelength of the third harmonic caused by replacing the light ball with the heavy one? Hint Young's Modulus for copper is 11 x 100 Pa Express your answer with the appropriate units. UA ? Δλ = Value m Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
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Transcribed Image Text: A Review Constants A vertical, 1.10 m length of 18 gauge (diameter of 1.024 mm) copper wire has a 100.0 N ball hanging from it. Express your answer with the appropriate units. X = 0.733 m Submit Previous Answers ✓ Correct Part B A 500.0 N ball now replaces the original ball. What is the change in the wavelength of the third harmonic caused by replacing the light ball with the heavy one? Hint Young's Modulus for copper is 11 x 100 Pa Express your answer with the appropriate units. UA ? Δλ = Value m Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
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We have, Length of copper wire rarr L=1.10m Change in length of copper wire rarr Delta L Diameter of copper wire rarr d=1.024mm=1.024 xx10^(-3)m Weight of ball rarr W=100N Change in the wight of the ball rarr Delta W=500N Young's Modulus of copperrarr E=11 xx10^(10)Pa Cross sectional area of the copper wire is calculated as: A=pi((d)/(2))^(2) :.A=pi((1.024 xx10^(-3))/(2))^(2) :.A=8.2355 xx10^(-7)m^(2)   Young modulus is given as a ratio ... See the full answer