# Question = A sawtooth signal u has the form u(t) = at/T for 0 <t<T, and is T-periodic (i.e., repeats every T seconds). The constant a is called the amplitude of the signal, and the constant T (which is positive) is called the period of the signal. You can assume that a > 0. a a (a) Find the peak value of a sawtooth signal. (b) Find the RMS (root-mean-square) value of a sawtooth signal. (c) Find the AA (average-absolute) value of a sawtooth signal. (d) In the space below, sketch the derivative of a sawtooth signal. Be sure to label all axes, slopes, magnitudes of any impulses, etc.

PVJ9K1 The Asker · Electrical Engineering

Transcribed Image Text: = A sawtooth signal u has the form u(t) = at/T for 0 0. a a (a) Find the peak value of a sawtooth signal. (b) Find the RMS (root-mean-square) value of a sawtooth signal. (c) Find the AA (average-absolute) value of a sawtooth signal. (d) In the space below, sketch the derivative of a sawtooth signal. Be sure to label all axes, slopes, magnitudes of any impulses, etc.
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Transcribed Image Text: = A sawtooth signal u has the form u(t) = at/T for 0 0. a a (a) Find the peak value of a sawtooth signal. (b) Find the RMS (root-mean-square) value of a sawtooth signal. (c) Find the AA (average-absolute) value of a sawtooth signal. (d) In the space below, sketch the derivative of a sawtooth signal. Be sure to label all axes, slopes, magnitudes of any impulses, etc.
Community Answer
N4HE74

Given Sqw tooth signal rarrSalytion{:[" By two point "rarr],[(0","0)" \&amp; "(T","q)],[y-y_(1)=((y_(2)-y_(1))/(x_(2)-x_(1)))*(x-x_(1))],[[U(t)-0)]=((9-0)/(T-0))(t-0)],[U(t)=(at)/(T)]:}(9) Peak Value =>V_("peat ")=9(b) Rms value =>" Rms "=sqrt((1)/(T)int_(0)^(T)[f(t)]^(2)dt)". \&amp; Generalised Form "{:[Rms=sqrt((1)/(T)int_(0)^(T)[u(d)]^(2)dt)quad u(d)=(qt)/(T)],[(Rms)^(2)=(1)/(T)int_(0)^(T)((qt)/(T))^(2)dt],[(Rms)^(2)=(1)/(T)((q^(2))/(T^(2)))int_(0)^(T)t^(2)*dt=>(Rms)^(2)=(1)/(T)((q^(2))/(T^(2) ... See the full answer