A steel rod having a cross-sectional area of 300 mm2 and a length of 150 m is suspended
vertically from one end. It supports a tensile load of 20 kN at the lower end. If the unit mass of
steel is 7850 kg/m3 and E = 200 × 103 MN/m2, find the total elongation of the rod.
Answer: s=54.33 mm
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arrow_forwardStep 1 IntroductionQuestion is based on steel rod suspended vertically from one end. Cross sectional area, length of bar, tensile load on bar and modulus of elasticity is given in the question . Elongation of rod needs to be determine.arrow_forwardStep 2 Data Given        Load on rod (P) = 20kN         Length of rod (l)= 150m         Area of rod (A) = 300 mm2Elasticity modulus(E)= 200 GPaarrow_forwardStep 3 Total elongation on rodTotal elongation in rod due to self weight (δ1):δ1 = PLAEδ1 = 7850×11000×3×9.81×300×150×1000300×200×103δ1 = 4.33 mmTotal elongation of beam δ2 due to applied Load :δ2 = 20×103×150×103300×200×103δ2 =50 mmTotal elongation (δ) :δ = δ1+δ2δ = 4.33+50δ = 54.33 mmarrow_forwardStep 4 ConclusionBased on above calculation, conclusion is as:Elongation of rod = 54.33 mm                              ...