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Step 1Step:1The Problem is based on Magnetic force due to a wire on another wire, Wsing the afractive force. on wire we can Calculate the current on the 2nd wire.Step 2Step:2The aftructive force on the 2 nd wire dire to current Carying by isf wire is given as.F=\frac{\mu_{0}}{4 \pi} \frac{2 I_{1} I_{2}}{\gamma}Where, I_{1} \rightarrow Corrent in lof wireI_{2} \rightarrow Corrent in and Wirer \rightarrow distance betwenn the wire\mathrm{H}_{0} \longrightarrow Magnetic PermiabillityF \rightarrow Force per unit lengthSo, I_{2}=\frac{F 4 \pi \gamma}{\mu_{0} 2 I_{1}}substitutiy the values we get\begin{array}{l}I_{2}=\frac{5.2 \times 10^{-4} \mathrm{~N} / \mathrm{m} \times 4 \pi \times 28 \times 10^{-2} \mathrm{~m}}{4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m} \times 2 \times 7 \mathrm{~A}} \\I_{2}=24 \mathrm{~A}\end{array} ...