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Given\begin{array}{l}O P=2.5 \mathrm{~km} \text { east }(t) \\P Q=6.9 \mathrm{~km} \text { west }(-) \\Q R=3.7 \mathrm{~km} \text { east }(t)\end{array}(a) Total distance of whall\begin{array}{l}S=O P+P Q+Q R \\S \Rightarrow 2 . S+6.9+3.7 \\S=13.10 \mathrm{~km}\end{array}Total distance covered by whale S=13 \cdot 10 \mathrm{~m} Answen(b) Total distabaerment of whale\begin{array}{l}\vec{B}=\overrightarrow{O P}+\overrightarrow{P Q}+\overrightarrow{Q R} \\\vec{S}=2.5-6.9+3.7 \\\vec{B}=-0.7\end{array}magnitude of Total disklacement of whale \varnothing=0.7 \mathrm{~km} & direction of tatal displacement of whale \rightarrow west.AnswerThank you!!! Please ud83dude4f rate it up. ...