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Magnetic force \Gamma=I L B \sin \thetawhere \theta is angle hetween current component and magnetic field.\begin{aligned}F & =I \angle B \sin \theta \\0.18 & =2.0 \times 0.60 \times 0.30 \times \sin \theta \\\sin \theta & =0.5 \\\theta & =\sin ^{-1}(0.5)=30^{\circ}\end{aligned}So, oplon 30^{\circ} is correct\odot 30^{\circ}Please upuole if you find it satesfac-tory. comment if doubt. ...