Question A wire loop of resistance 10 ohm and radius 10 cm is kept in the plane of this paper in a uniform magnetic field B. The direction of B is perpendicular to the plane of the page and points out of it and its magnitude is increasing at the rate of 0.50T/s. Determine the magnitude and direction of the induced current in the loop.

2020-03-06T10:24:08-0500 From the law of electromagnetic induction we write"\\epsilon=\\frac{\\Delta\\Phi}{\\Delta t}=\\frac{\\Delta(B \\cdot S)}{\\Delta t}=(\\frac{\\Delta B }{\\Delta t})\\cdot S" Where"S=\\pi \\cdot r^2" "(\\frac{\\Delta B }{\\Delta t})" -The rate of change of the magnetic fieldThen the current is"I=\\frac{\\epsilon}{R}=\\frac{(\\frac{\\Delta B }{\\Delta t})\\cdot S}{R}=\\frac{(\\frac{\\Delta B }{\\Delta t})\\cdot \\pi \\cdot r^2}{R}=\\frac{(0.5)\\cdot 3.14 \\cdot 0.1^2}{10}=1.57 mA" ...