An athlete exerts a tension of 6.00×102N on one end of a horizontal rope that has length 50.0 m and mass 2.50 kg. The other end is tied to a post. If she wiggles the rope with period 0.595 s and amplitude 3.00 cm, what is the angular frequency of the oscillation?
What is the average rate at which energy is transferred along the rope?
Use the following formula to find the angular frequency of the oscillations.{:[omega=(2pi)/(t)],[=(2(3.14))/(0.595(s))],[=10.55rad//s]:}The average rate the energy transferred along the rope is equal to the power.{:[P=(1)/(2)muomega ... See the full answer