An athlete exerts a tension of 6.00×102N on one end of a horizontal rope that has length 50.0 m and mass 2.50 kg. The other end is tied to a post. If she wiggles the rope with period 0.595 s and amplitude 3.00 cm, what is the angular frequency of the oscillation?

What is the average rate at which energy is transferred along the rope?

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Use the following formula to find the angular frequency of the oscillations.{:[omega=(2pi)/(t)],[=(2(3.14))/(0.595(s))],[=10.55rad//s]:}The average rate the energy transferred along the rope is equal to the power.{:[P=(1)/(2)muomega ... See the full answer