An athlete exerts a tension of 6.00×10^2 N on one end of a horizontal rope that has length 50.0 m and mass 2.50 kg. The other end is tied to a post. If she wiggles the rope with period 0.615 s and amplitude 3.00 cm, what is the angular frequency of the oscillation?

What is the average rate at which energy is transferred along the rope?

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Step 1Given data:t=0.615 sT=6×102 Nl=50 mm=2.5 kgA=3 cmNeed to determine the average rate at which energy is transferred along the rope.Step 2Calculate the angular frequency of oscillation.ω=2πt   =2×3.140.615   = ... See the full answer