# Question Solved1 AnswerAn electric field of $$250 \mathrm{~N} / \mathrm{C}$$, pointing due east, exerts a force on a $$3.5$$ $$\mu \mathrm{C}$$ charge. Determine the magnitude and direction of the force. $$2.63 \times 10^{-4} N$$, East $$8.75 \times 10^{-4} N$$, East $$8.75 \times 10^{-2} N$$, West $$8.75 \times 10^{-6} N$$, North $$4.38 \times 10^{-4} N$$, West $$An electric field of \( 250 \mathrm{~N} / \mathrm{C}$$, pointing due east, exerts a force on a $$3.5$$ $$\mu \mathrm{C}$$ charge. Determine the magnitude and direction of the force. $$2.63 \times 10^{-4} N$$, East $$8.75 \times 10^{-4} N$$, East $$8.75 \times 10^{-2} N$$, West $$8.75 \times 10^{-6} N$$, North $$4.38 \times 10^{-4} N$$, West $$14 \times 10^{-9} N$$, West$$71.4 \times 10^{-6} N$$, South $$3.06 \times 10^{-4} N$$, East

Transcribed Image Text: An electric field of $$250 \mathrm{~N} / \mathrm{C}$$, pointing due east, exerts a force on a $$3.5$$ $$\mu \mathrm{C}$$ charge. Determine the magnitude and direction of the force. $$2.63 \times 10^{-4} N$$, East $$8.75 \times 10^{-4} N$$, East $$8.75 \times 10^{-2} N$$, West $$8.75 \times 10^{-6} N$$, North $$4.38 \times 10^{-4} N$$, West $$14 \times 10^{-9} N$$, West $$71.4 \times 10^{-6} N$$, South $$3.06 \times 10^{-4} N$$, East
Transcribed Image Text: An electric field of $$250 \mathrm{~N} / \mathrm{C}$$, pointing due east, exerts a force on a $$3.5$$ $$\mu \mathrm{C}$$ charge. Determine the magnitude and direction of the force. $$2.63 \times 10^{-4} N$$, East $$8.75 \times 10^{-4} N$$, East $$8.75 \times 10^{-2} N$$, West $$8.75 \times 10^{-6} N$$, North $$4.38 \times 10^{-4} N$$, West $$14 \times 10^{-9} N$$, West $$71.4 \times 10^{-6} N$$, South $$3.06 \times 10^{-4} N$$, East