Question An electron moves along the z-axis with vz=2.1×107m/s. As it passes the origin, what are the strength and direction of the magnetic field at the following (x, y, z) positions? (0 cm, 0 cm, 2 cm ), (0 cm, 2 cm , 2 cm )
L062R6 The Asker · Physics
An electron moves along the z-axis with vz=2.1×107m/s. As it passes the origin, what are the strength and direction of the magnetic field at the following (x, y, z) positions? (0 cm, 0 cm, 2 cm ), (0 cm, 2 cm , 2 cm )
Transcribed Image Text: An electron moves along the z-axis
with vz=2.1×107m/s. As it passes the origin,
what are the strength and direction of the magnetic field at the
following (x, y, z)
positions? (0 cm, 0 cm,
2 cm ), (0 cm, 2 cm ,
2 cm )
More Transcribed Image Text: An electron moves along the z-axis
with vz=2.1×107m/s. As it passes the origin,
what are the strength and direction of the magnetic field at the
following (x, y, z)
positions? (0 cm, 0 cm,
2 cm ), (0 cm, 2 cm ,
2 cm )
Community Answer
LSGCDX
At posotian (0,0,2)cm :farmuld far magnetic field due to do charge particle isB=(mu_(0)q( vec(v))xx( hat(r)))/(4pir^(2))In this case the magnetic field is to be calculated an z-axis{:[ vec(v)xx hat(r)=0],[:.B=0quad T]:}At posotian (0,2,2)cm :{:[B=(mu_(0)qV sin theta)/(4pir^(2))],[r=sqrt(0.02^(2)+0.02^(2))=2 ... See the full answer