An electron travels with speed 0.70×107m/s between the two parallel charged plates shown in the figure(Figure 1) . The plates are separated by 1.0 cm and are charged by a 200 V battery. What magnetic field strength will allow the electron to pass between the plates without being deflected?
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apply Electric field E  = V/d E  =  200/0.01E  =  2e 4 V/m now the relation between EF anf magnetic field B is E =  Bv B  =  E/v B  =  2e4/(0.7 e7)B  =  2.85 mT   ...