Question Solved1 Answer An electron with speed 2.40x107 m/s is traveling parallel to a uniform electric field of magnitude 1.13x104 N/C Part A How far will the electron travel before it stops? IVO AO ? Δε = = Submit Request Answer Part B How much time will elapse before it returns to its starting point? IVO AE ? t Submit Request Answer

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Transcribed Image Text: An electron with speed 2.40x107 m/s is traveling parallel to a uniform electric field of magnitude 1.13x104 N/C Part A How far will the electron travel before it stops? IVO AO ? Δε = = Submit Request Answer Part B How much time will elapse before it returns to its starting point? IVO AE ? t Submit Request Answer
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Transcribed Image Text: An electron with speed 2.40x107 m/s is traveling parallel to a uniform electric field of magnitude 1.13x104 N/C Part A How far will the electron travel before it stops? IVO AO ? Δε = = Submit Request Answer Part B How much time will elapse before it returns to its starting point? IVO AE ? t Submit Request Answer
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Force =Q X E  Q=charge ;E=electric filed  Q x E= mass x acceleration  Acceleration = QE/m =1.6x10-19 x 1.13 x 104/9.1 x 10-31 =1.97 x 1016m/s2 1) initial velocity = 2.4 x 107m/s Final velocity =0 By applying equation of motion  V ... See the full answer