An FM transmitter operates with a total power of 10 Watts, a deviation of 5 kHz, and a modulation index of 2

If the receiver has a bandwidth sufficient to include the carrier and the first two sets of sidebands, what percentage of the total signal power will it receive?

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Total power transmitted =P_{T}=\frac{A_{C}^{2}}{2}=10 \mathrm{~W}Deviation. \Delta f=5 \mathrm{kh} 3modulation \beta=2index.Receiver has Bandwidth to receivecasrier and first two side bandp.\Rightarrow Receiver Received the componentsFrom Bessel Function table for T_{n}(x)\begin{array}{l}J_{0}(2)=0.22 \\J_{1}(2)=0.58 \\J_{2(2)}=0.35\end{array}\rightarrow x=2Received power P_{k}=\frac{\left(A c J_{0}(2)\right)^{2}}{2}+\frac{\left.y_{1} \cdot A C J_{1}(2)\right)^{2}}{2}+\left.\frac{(2)\left(A<-J_{2}(2)\right)}{2}\right)^{2}\begin{array}{l}P_{R}=\frac{A C^{2}}{2}\left\{J_{0}(2)^{2}+2 J_{1}(2)^{2}+2 J_{2}(2)^{2}\right\} \\\frac{P_{R}}{P_{T}}=0.9662 \\\frac{P_{R}}{P_{T}}=96.62 \%\end{array} ...