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(1)\begin{array}{l}\text { UT }=15 \mathrm{~V} \\\text { UGS }=4 \mathrm{~V}\end{array}as vGS 7 V7 lt means mosfer is on(1)Ups(sat)Yer saluralon\begin{aligned}\text { VDS } \geqslant & \left(U G S-v_{7}\right) \\\text { VDS sat }= & U G S-v_{7} \\& -4-1.5=2-5 v\end{aligned}(1) UDS =14 \mathrm{~V}in saluation\begin{array}{l}I_{D=k n\left(U G s-V_{T}\right)^{2}} \\\left.I_{D=3}=3-1.5\right)^{2}=18-75 \mathrm{~mA}\end{array}(ill\begin{aligned}g_{m}=\frac{\partial I D}{\partial U G S} \quad= & \frac{\partial}{\partial V G s}(v G s-v)^{2} \\& =2 k n(v G s-v-1) \\& =2 \times 3 \times(4-1.5) \\& =6 \times 2.5=15 \mathrm{~ms}\end{aligned}(b) non saluratien regien / lurear regrenI_{D}, \quad \ln \left(2\left(U G S-V_{1}\right) v D s-V_{D S}^{2}\right)\begin{aligned}\therefore V_{D S}= & 0.4 \mathrm{~V} \\I_{D}= & 3\left(2(4-1.5) 0.4-0.4^{2}\right) \\& 3(2 \times 2.5 \times 0.4-0.16)=5.52 \mathrm{~mA}\end{aligned}(V)gon for linear lineán\begin{aligned}g_{m}=\frac{\partial I D}{\partial V G S} & =\frac{\partial}{\partial V G S}\left[k n\left(2(V G S-V T H) V \Delta S-v_{D}^{2}\right]\right. \\& =2 \mathrm{kn} V D S \\& =2 \times B \times 0.4 \\& =2.4 \mathrm{~ms}\end{aligned}Ans- (a) 2.5 \mathrm{v}(b) 18.75 \mathrm{~mA}(C) 15 \mathrm{~ms}(d) 5.52 \mathrm{~mA}(e) 2.4 \mathrm{~ms} ...