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/An object is located in air 55 cm from the vertex of a concave surface made of glass with a radius of curvature 20 cm. Where does the image by refraction form? Use nair = 1 and glass = 1.5. (Give the image distance in centimeters with the appropriate sign.) HINTS: For the sign on the focal length, the glass is concave. For the sign on R, the object is in the air side, not the glass side. -34.7 cm What is its magnification? m = 0.63 x

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An object is located in air 55 cm from the vertex of a concave surface made of glass with a radius of curvature 20 cm. Where does the image by refraction form? Use nair = 1 and glass = 1.5. (Give the image distance in centimeters with the appropriate sign.) HINTS: For the sign on the focal length, the glass is concave. For the sign on R, the object is in the air side, not the glass side. -34.7 cm What is its magnification? m = 0.63 x

N7GGD1The Asker · Physics

Transcribed Image Text: An object is located in air 55 cm from the vertex of a concave surface made of glass with a radius of curvature 20 cm. Where does the image by refraction form? Use nair = 1 and glass = 1.5. (Give the image distance in centimeters with the appropriate sign.) HINTS: For the sign on the focal length, the glass is concave. For the sign on R, the object is in the air side, not the glass side. -34.7 cm What is its magnification? m = 0.63 x

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Transcribed Image Text: An object is located in air 55 cm from the vertex of a concave surface made of glass with a radius of curvature 20 cm. Where does the image by refraction form? Use nair = 1 and glass = 1.5. (Give the image distance in centimeters with the appropriate sign.) HINTS: For the sign on the focal length, the glass is concave. For the sign on R, the object is in the air side, not the glass side. -34.7 cm What is its magnification? m = 0.63 x

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n_("air ")=1quad{:[R=-20cm],[" and "n_("glass ")=1.5]:}Using the equation{:[(n_(2))/(d_(i))=(n_(2)-n_(1))/(R)-(n_(1))/(d_(0))],[(1.5)/(d_(i))=(1. ... See the full answer