An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a bag of tools. First he tries to throw a rope to his fellow astronaut, but the rope is too short. In a last ditch effort, the astronaut throws his bag of tools in the direction of his motion, away from the space station. The astronaut has a mass of ?a=113 kg and the bag of tools has a mass of ?b=19.0 kg. If the astronaut is moving away from the space station at ?i=1.20 m/s initially, what is the minimum final speed ?b,f of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever?
Step 1Solution:Given values,m1 = mass of astronaut = 113 Kg m2 = mass of tool bag = 19 Kg u1 = u2 = 1.20 m/s before the astronaut throw the tool bag      Step 2By use of conservation of momentum: We have,m1u1 + m2u2 = m1v1 + m2v2In or ... See the full answer