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Area of square =144cm^(2) Hence side of square =sqrt144=12cm. maximum errop toterance in the area =8cm^(2)so by the definition of delta epsilon if sigma < |x-a| < delta the |f(x)-L| < xiwe are given L=144,a=12,xi_(G)=8 now we find deltaArea of square =x^(2) where x is the side of square f(x)=x^(2) and{:[lim_(x rarr12)f(x)=L=144],[|f(x ... See the full answer