Question APPLICATION PROBLEM: Voltage dividers are widely used in electronics. One application is shown in the regulated power supply circuit in Figure 7-6. A fraction of the regulated output voltage is returned to the comparator by the voltage divider. The comparator, in turn, compares the voltage divider output with a constant voltage source and controls the series APPLICATION PROBLEM: Voltage dividers are widely used in electronics. One application is shown in the regulated power supply circuit in Figure 7-6. A fraction of the regulated output voltage is returned to the comparator by the voltage divider. The comparator, in turn, compares the voltage divider output with a constant voltage source and controls the series regulator. The requirements for the voltage divider are as follows: 1. There should be a minimum of \( 3 \mathrm{~mA} \) of current in the divider string. There is no current required by the comparator. 2. The regulated output voltage depends on the position of the variable-tap on \( R_{1} \). When \( R_{1} \) is at the highest position (see Figure 7-6(b)), the regulated output voltage and the voltage divider output are both \( 10.0 \mathrm{~V} \). 3. When \( R_{1} \) is at the lowest position (see Figure 7-6(c)), the regulated output voltage rises to \( 15.0 \mathrm{~V} \) and the voltage divider output is still \( 10.0 \mathrm{~V} \). Compute the resistors that will satisfy the design requirements. Test your circuit using a variable power supply to simulate the output of the series regulator and show your results in the Application Problem part of your report. (b) (a) (c) Figure 7-6 80

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Transcribed Image Text: APPLICATION PROBLEM: Voltage dividers are widely used in electronics. One application is shown in the regulated power supply circuit in Figure 7-6. A fraction of the regulated output voltage is returned to the comparator by the voltage divider. The comparator, in turn, compares the voltage divider output with a constant voltage source and controls the series regulator. The requirements for the voltage divider are as follows: 1. There should be a minimum of \( 3 \mathrm{~mA} \) of current in the divider string. There is no current required by the comparator. 2. The regulated output voltage depends on the position of the variable-tap on \( R_{1} \). When \( R_{1} \) is at the highest position (see Figure 7-6(b)), the regulated output voltage and the voltage divider output are both \( 10.0 \mathrm{~V} \). 3. When \( R_{1} \) is at the lowest position (see Figure 7-6(c)), the regulated output voltage rises to \( 15.0 \mathrm{~V} \) and the voltage divider output is still \( 10.0 \mathrm{~V} \). Compute the resistors that will satisfy the design requirements. Test your circuit using a variable power supply to simulate the output of the series regulator and show your results in the Application Problem part of your report. (b) (a) (c) Figure 7-6 80
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Transcribed Image Text: APPLICATION PROBLEM: Voltage dividers are widely used in electronics. One application is shown in the regulated power supply circuit in Figure 7-6. A fraction of the regulated output voltage is returned to the comparator by the voltage divider. The comparator, in turn, compares the voltage divider output with a constant voltage source and controls the series regulator. The requirements for the voltage divider are as follows: 1. There should be a minimum of \( 3 \mathrm{~mA} \) of current in the divider string. There is no current required by the comparator. 2. The regulated output voltage depends on the position of the variable-tap on \( R_{1} \). When \( R_{1} \) is at the highest position (see Figure 7-6(b)), the regulated output voltage and the voltage divider output are both \( 10.0 \mathrm{~V} \). 3. When \( R_{1} \) is at the lowest position (see Figure 7-6(c)), the regulated output voltage rises to \( 15.0 \mathrm{~V} \) and the voltage divider output is still \( 10.0 \mathrm{~V} \). Compute the resistors that will satisfy the design requirements. Test your circuit using a variable power supply to simulate the output of the series regulator and show your results in the Application Problem part of your report. (b) (a) (c) Figure 7-6 80
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【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/1Hi,To determine the values of R1 and R2, convert the information given in points 1,2 and 3 into equations:10R1+R2=0.003 ...from specifications 1 and 2 15*R2/(R1+R2) = 10 .......This is from specification 3Simplifying the first equation we get:0.003*R1 + 0.003*R2 = 10 ............equ (3)Simplifying the second equation we get15*R2 = 10*R1+10*R2Therefore5*R2 = 10*R1R2 = 2*R1Substituting this in eq. (3 ... See the full answer